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| Author : | Topic: Are the eigenvectors of a diagonal matrix always orthogonal? | Bottom |
| zee Posts : 115 |
Diagonalization represents a change of basis to a basis of eigenvectors. 1. A matrix, that is diagonal in the basis unit vectors (1,0,0..0), (0,1,0..0) etc. has just these unit vectors as eigenvectors. And they are clearly orthogonal. 2. A non-symmetric n by n matrix of full rank (with indepedent columns) does not in general have a full rank n by n matrix of eigenvectors. Thus you ar not in general able to diagonalize it. Anyway... Changing to a basis, which is not orthogonal you can visualize as a warping of the entire space as to make the basis orthogonal. The resulting diagonal matrix of your example only has orthogonal columns in the sense that they are in the same directions as the basis of eigenvectors. Change of bases is an important concept, but can seem difficult. For a geometric approach to understanding eigenvalues and -vectors se lecture 20 of the OCW course on tensors http://ocw.mit.edu/OcwWeb/Materials-Science-and-Engineering/3-60Fall-2005/VideoLectures/index.htm Keep in mind that a second rank tensor (rank meens something else here) can be represented simply by a matrix. --Last edited by zee on 2007-01-25 20:04:31 -- |
| ferme Posts : 85 |
** Let V be a vector space and T: V→V be a linear transformation. A scalar is called an eigen-value for T if there exists a non-zero vector vV such that Tv = λv. The non-zero vector v is called an eigenvector for the eigenvalue λ .** http://www.mathresource.iitb.ac.in/linear%20algebra/mainchapter9.4.html --Last edited by ferme on 2007-02-26 08:40:26 -- |
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