If we look for logic quite often we can find the solution but if we look too far into the subject we begin to ask ourselves too many problems so we see a prob use yourself just as a reference & deal just with that topic without reason just logic....here is a light hearted guide for all to get familiar & enjoy Maths....

http://nrich.maths.org/public/index.php  

--Last edited by us2u on 2006-12-27 17:09:40 --

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Department of Mathematics
Purdue University, Indiana.

Purdue Math Problems


http://www.math.purdue.edu/pow/


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--Last edited by saucer on 2007-01-13 16:53:15 --

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Sequences quiz

http://www.research.att.com/~njas/sequences/

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The On-line Journal for Mathematical Recreations


In most introductions to number theory there is mention of the Sieve of Eratosthenes, which is constructed by making a list of numbers from 2 upwards as far as some number N, then striking out all multiples of the first number in the sequence (but not the number itself), then all multiples of the second remaining number in the sequence, then all multiples of the third remaining number in the sequence and so on, as far as the square root of N. The final result is a list of the prime numbers up to N.

Here is a puzzle based on this sieving process. The numbers struck out beginning at p are p×2, p×3, p×4, ... that is numbers of the form p×m where the factor m is continually increased by 1 while the other p, the prime, is kept constant. Generalising this process I call a move from p×q to p×(q+1) or to p×(q–1) or to (p+1)×q or to (p–1)×q, where the unchanged factor must be a prime number, a footstep of Eratosthenes and a series of such moves a path of Eratosthenes. By permitting either factor to be varied and to increase or decrease by 1 in this way more complex paths than simple progressions are possible../




http://www.gpj.connectfree.co.uk/gpji.htm

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Math tricks


http://www.angelfire.com/me/marmalade/mathtips.html

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http://www.mcs.surrey.ac.uk/Personal/R.Knott/Fibonacci/fibmaths.html



saucer





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advanced problem



Consider the equation tan x = x. Let xn denote the (unique) root of this equation that lies in the interval ((2n − 1) pi/2, (2n + 1) pi/2). For example, x0 = 0, x1 is approximately 4.49341, and x2 is approximately 7.72525. [Note: In the graph below, the axes are scaled differently.]

evaluate




 

--Last edited by experi-momentum on 2007-08-27 00:27:18 --